0.25x^2+1.25x+1=0

Solution for 0.25x^2+1.25x+1=0 equation:

0.25x^2+1.25x+1=0

a = 0.25; b = 1.25; c = +1;
Δ = b2-4ac
Δ = 1.252-4·0.25·1
Δ = 0.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.25)-\sqrt{0.5625}}{2*0.25}=\frac{-1.25-\sqrt{0.5625}}{0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.25)+\sqrt{0.5625}}{2*0.25}=\frac{-1.25+\sqrt{0.5625}}{0.5}
$